(20+x)+(x)=(4x-100)

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Solution for (20+x)+(x)=(4x-100) equation: 



(20+x)+(x)=(4x-100)

We move all terms to the left:

(20+x)+(x)-((4x-100))=0

We add all the numbers together, and all the variables

(x+20)+x-((4x-100))=0

We add all the numbers together, and all the variables

x+(x+20)-((4x-100))=0

We get rid of parentheses

x+x-((4x-100))+20=0



We calculate terms in parentheses: -((4x-100)), so:

(4x-100)

We get rid of parentheses

4x-100

Back to the equation:

-(4x-100)



We add all the numbers together, and all the variables

2x-(4x-100)+20=0

We get rid of parentheses

2x-4x+100+20=0

We add all the numbers together, and all the variables

-2x+120=0

We move all terms containing x to the left, all other terms to the right

-2x=-120

x=-120/-2

x=+60

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