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(20-2x)(14-2x)=228
We move all terms to the left:
(20-2x)(14-2x)-(228)=0
We add all the numbers together, and all the variables
(-2x+20)(-2x+14)-228=0
We multiply parentheses ..
(+4x^2-28x-40x+280)-228=0
We get rid of parentheses
4x^2-28x-40x+280-228=0
We add all the numbers together, and all the variables
4x^2-68x+52=0
a = 4; b = -68; c = +52;
Δ = b2-4ac
Δ = -682-4·4·52
Δ = 3792
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3792}=\sqrt{16*237}=\sqrt{16}*\sqrt{237}=4\sqrt{237}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-68)-4\sqrt{237}}{2*4}=\frac{68-4\sqrt{237}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-68)+4\sqrt{237}}{2*4}=\frac{68+4\sqrt{237}}{8} $
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