(20-2x)(32-2x)=540

Solution for (20-2x)(32-2x)=540 equation:

(20-2x)(32-2x)=540

We move all terms to the left:

(20-2x)(32-2x)-(540)=0

We add all the numbers together, and all the variables

(-2x+20)(-2x+32)-540=0

We multiply parentheses ..

(+4x^2-64x-40x+640)-540=0

We get rid of parentheses

4x^2-64x-40x+640-540=0

We add all the numbers together, and all the variables

4x^2-104x+100=0

a = 4; b = -104; c = +100;
Δ = b2-4ac
Δ = -1042-4·4·100
Δ = 9216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9216}=96$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-104)-96}{2*4}=\frac{8}{8}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-104)+96}{2*4}=\frac{200}{8}
=25
$