(20-2x)+(6x+20)=32

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Solution for (20-2x)+(6x+20)=32 equation:



(20-2x)+(6x+20)=32
We move all terms to the left:
(20-2x)+(6x+20)-(32)=0
We add all the numbers together, and all the variables
(-2x+20)+(6x+20)-32=0
We get rid of parentheses
-2x+6x+20+20-32=0
We add all the numbers together, and all the variables
4x+8=0
We move all terms containing x to the left, all other terms to the right
4x=-8
x=-8/4
x=-2

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