(20-2x)=(110-22x)

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Solution for (20-2x)=(110-22x) equation: 



(20-2x)=(110-22x)

We move all terms to the left:

(20-2x)-((110-22x))=0

We add all the numbers together, and all the variables

(-2x+20)-((-22x+110))=0

We get rid of parentheses

-2x-((-22x+110))+20=0



We calculate terms in parentheses: -((-22x+110)), so:

(-22x+110)

We get rid of parentheses

-22x+110

Back to the equation:

-(-22x+110)



We get rid of parentheses

-2x+22x-110+20=0

We add all the numbers together, and all the variables

20x-90=0

We move all terms containing x to the left, all other terms to the right

20x=90

x=90/20

x=4+1/2

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