(20-3x)=(110-23x)

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Solution for (20-3x)=(110-23x) equation: 



(20-3x)=(110-23x)

We move all terms to the left:

(20-3x)-((110-23x))=0

We add all the numbers together, and all the variables

(-3x+20)-((-23x+110))=0

We get rid of parentheses

-3x-((-23x+110))+20=0



We calculate terms in parentheses: -((-23x+110)), so:

(-23x+110)

We get rid of parentheses

-23x+110

Back to the equation:

-(-23x+110)



We get rid of parentheses

-3x+23x-110+20=0

We add all the numbers together, and all the variables

20x-90=0

We move all terms containing x to the left, all other terms to the right

20x=90

x=90/20

x=4+1/2

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