(20-4i)/(3+2i)=4-4i

Solution for (20-4i)/(3+2i)=4-4i equation:

(20-4i)/(3+2i)=4-4i

We move all terms to the left:

(20-4i)/(3+2i)-(4-4i)=0


Domain of the equation: (3+2i)!=0

We move all terms containing i to the left, all other terms to the right

2i!=-3

i!=-3/2

i!=-1+1/2

i∈R


We add all the numbers together, and all the variables

(-4i+20)/(2i+3)-(-4i+4)=0

We get rid of parentheses

(-4i+20)/(2i+3)+4i-4=0

We multiply all the terms by the denominator


(-4i+20)+4i*(2i+3)-4*(2i+3)=0

We multiply parentheses

8i^2+(-4i+20)+12i-8i-12=0

We get rid of parentheses

8i^2-4i+12i-8i+20-12=0

We add all the numbers together, and all the variables

8i^2+8=0

a = 8; b = 0; c = +8;
Δ = b2-4ac
Δ = 02-4·8·8
Δ = -256
Delta is less than zero, so there is no solution for the equation