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(20-5x)(20+5x)=0
We add all the numbers together, and all the variables
(-5x+20)(5x+20)=0
We multiply parentheses ..
(-25x^2-100x+100x+400)=0
We get rid of parentheses
-25x^2-100x+100x+400=0
We add all the numbers together, and all the variables
-25x^2+400=0
a = -25; b = 0; c = +400;
Δ = b2-4ac
Δ = 02-4·(-25)·400
Δ = 40000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{40000}=200$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-200}{2*-25}=\frac{-200}{-50} =+4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+200}{2*-25}=\frac{200}{-50} =-4 $
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