(20-6x)(30-4x)=V

Solution for (20-6x)(30-4x)=V equation:

(20-6x)(30-4x)=

We move all terms to the left:

(20-6x)(30-4x)-()=0

We add all the numbers together, and all the variables

(-6x+20)(-4x+30)-()=0

We add all the numbers together, and all the variables

(-6x+20)(-4x+30)=0

We multiply parentheses ..

(+24x^2-180x-80x+600)=0

We get rid of parentheses

24x^2-180x-80x+600=0

We add all the numbers together, and all the variables

24x^2-260x+600=0

a = 24; b = -260; c = +600;
Δ = b2-4ac
Δ = -2602-4·24·600
Δ = 10000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{10000}=100$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-260)-100}{2*24}=\frac{160}{48}
=3+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-260)+100}{2*24}=\frac{360}{48}
=7+1/2
$