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(20-6x=4x-15.x)
We move all terms to the left:
(20-6x-(4x-15.x))=0
We add all the numbers together, and all the variables
(20-6x-(-11x))=0
We calculate terms in parentheses: +(20-6x-(-11x)), so:We get rid of parentheses
20-6x-(-11x)
determiningTheFunctionDomain -6x-(-11x)+20
We get rid of parentheses
-6x+11x+20
We add all the numbers together, and all the variables
5x+20
Back to the equation:
+(5x+20)
5x+20=0
We move all terms containing x to the left, all other terms to the right
5x=-20
x=-20/5
x=-4
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