(20-x-(2x-5))+x+(2x-5)=20

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Solution for (20-x-(2x-5))+x+(2x-5)=20 equation: 



(20-x-(2x-5))+x+(2x-5)=20

We move all terms to the left:

(20-x-(2x-5))+x+(2x-5)-(20)=0

We add all the numbers together, and all the variables

x+(20-x-(2x-5))+(2x-5)-20=0

We get rid of parentheses

x+(20-x-(2x-5))+2x-5-20=0



We calculate terms in parentheses: +(20-x-(2x-5)), so:

20-x-(2x-5)

determiningTheFunctionDomain
-x-(2x-5)+20

We add all the numbers together, and all the variables

-1x-(2x-5)+20

We get rid of parentheses

-1x-2x+5+20

We add all the numbers together, and all the variables

-3x+25

Back to the equation:

+(-3x+25)



We add all the numbers together, and all the variables

3x+(-3x+25)-25=0

We get rid of parentheses

3x-3x+25-25=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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