(20/(p-4))-((5p)/(p-4))

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Solution for (20/(p-4))-((5p)/(p-4)) equation:


D( p )

p-4 = 0

p-4 = 0

p-4 = 0

p-4 = 0 // + 4

p = 4

p in (-oo:4) U (4:+oo)

20/(p-4)-((5*p)/(p-4)) = 0

20/(p-4)-5*p*(p-4)^-1 = 0

20/(p-4)+(-5*p)/(p-4) = 0

20-5*p = 0

(20-5*p)/(p-4) = 0

(20-5*p)/(p-4) = 0 // * p-4

20-5*p = 0

20-5*p = 0 // - 20

-5*p = -20 // : -5

p = -20/(-5)

p = 4

p in { 4}

p belongs to the empty set

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