(20/3)+(14/3)y=0

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Solution for (20/3)+(14/3)y=0 equation: 



(20/3)+(14/3)y=0



Domain of the equation: 3)y!=0

y!=0/1

y!=0

y∈R



We add all the numbers together, and all the variables

(+14/3)y+(+20/3)=0

We multiply parentheses

14y^2+(+20/3)=0

We get rid of parentheses

14y^2+20/3=0

We multiply all the terms by the denominator


14y^2*3+20=0

Wy multiply elements

42y^2+20=0

a = 42; b = 0; c = +20;
Δ = b2-4ac
Δ = 02-4·42·20
Δ = -3360
Delta is less than zero, so there is no solution for the equation

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