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(200+60x)/(5+x)=52
We move all terms to the left:
(200+60x)/(5+x)-(52)=0
Domain of the equation: (5+x)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
x!=-5
x∈R
(60x+200)/(x+5)-52=0
We multiply all the terms by the denominator
(60x+200)-52*(x+5)=0
We multiply parentheses
(60x+200)-52x-260=0
We get rid of parentheses
60x-52x+200-260=0
We add all the numbers together, and all the variables
8x-60=0
We move all terms containing x to the left, all other terms to the right
8x=60
x=60/8
x=7+1/2
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