(20=2+3b)

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Solution for (20=2+3b) equation: 



(20=2+3b)

We move all terms to the left:

(20-(2+3b))=0

We add all the numbers together, and all the variables

(20-(3b+2))=0



We calculate terms in parentheses: +(20-(3b+2)), so:

20-(3b+2)

determiningTheFunctionDomain
-(3b+2)+20

We get rid of parentheses

-3b-2+20

We add all the numbers together, and all the variables

-3b+18

Back to the equation:

+(-3b+18)



We get rid of parentheses

-3b+18=0

We move all terms containing b to the left, all other terms to the right

-3b=-18

b=-18/-3

b=+6

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