(20x/(4x-1))+(2/x)=5

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Solution for (20x/(4x-1))+(2/x)=5 equation: 


D( x )

4*x-1 = 0

x = 0

4*x-1 = 0

4*x-1 = 0

4*x-1 = 0 // + 1

4*x = 1 // : 4

x = 1/4

x = 0

x = 0

x in (-oo:0) U (0:1/4) U (1/4:+oo)

(20*x)/(4*x-1)+2/x = 5 // - 5

(20*x)/(4*x-1)+2/x-5 = 0

(20*x*x)/(x*(4*x-1))+(2*(4*x-1))/(x*(4*x-1))+(-5*x*(4*x-1))/(x*(4*x-1)) = 0

2*(4*x-1)-5*x*(4*x-1)+20*x*x = 0

20*x^2-20*x^2+8*x+5*x-2 = 0

13*x-2 = 0

(13*x-2)/(x*(4*x-1)) = 0

(13*x-2)/(x*(4*x-1)) = 0 // * x*(4*x-1)

13*x-2 = 0

13*x-2 = 0 // + 2

13*x = 2 // : 13

x = 2/13

x = 2/13

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