(20y-11)=(4y+6)=(7y-7)

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Solution for (20y-11)=(4y+6)=(7y-7) equation: 



(20y-11)=(4y+6)=(7y-7)

We move all terms to the left:

(20y-11)-((4y+6))=0

We get rid of parentheses

20y-((4y+6))-11=0



We calculate terms in parentheses: -((4y+6)), so:

(4y+6)

We get rid of parentheses

4y+6

Back to the equation:

-(4y+6)



We get rid of parentheses

20y-4y-6-11=0

We add all the numbers together, and all the variables

16y-17=0

We move all terms containing y to the left, all other terms to the right

16y=17

y=17/16

y=1+1/16

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