(21+10x)=(3x+28)

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Solution for (21+10x)=(3x+28) equation: 



(21+10x)=(3x+28)

We move all terms to the left:

(21+10x)-((3x+28))=0

We add all the numbers together, and all the variables

(10x+21)-((3x+28))=0

We get rid of parentheses

10x-((3x+28))+21=0



We calculate terms in parentheses: -((3x+28)), so:

(3x+28)

We get rid of parentheses

3x+28

Back to the equation:

-(3x+28)



We get rid of parentheses

10x-3x-28+21=0

We add all the numbers together, and all the variables

7x-7=0

We move all terms containing x to the left, all other terms to the right

7x=7

x=7/7

x=1

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