(21+p)(34+3p)(27+3p)=180

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Solution for (21+p)(34+3p)(27+3p)=180 equation: 



(21+p)(34+3p)(27+3p)=180

We move all terms to the left:

(21+p)(34+3p)(27+3p)-(180)=0

We add all the numbers together, and all the variables

(p+21)(3p+34)(3p+27)-180=0

We multiply parentheses ..

(+3p^2+34p+63p+714)(3p+27)-180=0

We move all terms containing p to the left, all other terms to the right

(+3p^2+34p+63p+714)(3p+27)=180

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