(21+x)+(34+3x)+(27+3x)=180

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Solution for (21+x)+(34+3x)+(27+3x)=180 equation: 



(21+x)+(34+3x)+(27+3x)=180

We move all terms to the left:

(21+x)+(34+3x)+(27+3x)-(180)=0

We add all the numbers together, and all the variables

(x+21)+(3x+34)+(3x+27)-180=0

We get rid of parentheses

x+3x+3x+21+34+27-180=0

We add all the numbers together, and all the variables

7x-98=0

We move all terms containing x to the left, all other terms to the right

7x=98

x=98/7

x=14

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