(21-4x)(21-4x)=0

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Solution for (21-4x)(21-4x)=0 equation: 



(21-4x)(21-4x)=0

We add all the numbers together, and all the variables

(-4x+21)(-4x+21)=0

We multiply parentheses ..

(+16x^2-84x-84x+441)=0

We get rid of parentheses

16x^2-84x-84x+441=0

We add all the numbers together, and all the variables

16x^2-168x+441=0

a = 16; b = -168; c = +441;
Δ = b2-4ac
Δ = -1682-4·16·441
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{168}{32}=5+1/4$

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