(21/25)x=1635

Solution for (21/25)x=1635 equation:

(21/25)x=1635

We move all terms to the left:

(21/25)x-(1635)=0


Domain of the equation: 25)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+21/25)x-1635=0

We multiply parentheses

21x^2-1635=0

a = 21; b = 0; c = -1635;
Δ = b2-4ac
Δ = 02-4·21·(-1635)
Δ = 137340
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{137340}=\sqrt{36*3815}=\sqrt{36}*\sqrt{3815}=6\sqrt{3815}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{3815}}{2*21}=\frac{0-6\sqrt{3815}}{42}
=-\frac{6\sqrt{3815}}{42}
=-\frac{\sqrt{3815}}{7}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{3815}}{2*21}=\frac{0+6\sqrt{3815}}{42}
=\frac{6\sqrt{3815}}{42}
=\frac{\sqrt{3815}}{7}
$