(21b-4)-5(4b+3)=-4

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Solution for (21b-4)-5(4b+3)=-4 equation: 



(21b-4)-5(4b+3)=-4

We move all terms to the left:

(21b-4)-5(4b+3)-(-4)=0

We add all the numbers together, and all the variables

(21b-4)-5(4b+3)+4=0

We multiply parentheses

(21b-4)-20b-15+4=0

We get rid of parentheses

21b-20b-4-15+4=0

We add all the numbers together, and all the variables

b-15=0

We move all terms containing b to the left, all other terms to the right

b=15

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