(21x+1)+(11x+1)+50=180

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Solution for (21x+1)+(11x+1)+50=180 equation: 



(21x+1)+(11x+1)+50=180

We move all terms to the left:

(21x+1)+(11x+1)+50-(180)=0

We add all the numbers together, and all the variables

(21x+1)+(11x+1)-130=0

We get rid of parentheses

21x+11x+1+1-130=0

We add all the numbers together, and all the variables

32x-128=0

We move all terms containing x to the left, all other terms to the right

32x=128

x=128/32

x=4

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