(21x-19)=(7x+31)

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Solution for (21x-19)=(7x+31) equation: 



(21x-19)=(7x+31)

We move all terms to the left:

(21x-19)-((7x+31))=0

We get rid of parentheses

21x-((7x+31))-19=0



We calculate terms in parentheses: -((7x+31)), so:

(7x+31)

We get rid of parentheses

7x+31

Back to the equation:

-(7x+31)



We get rid of parentheses

21x-7x-31-19=0

We add all the numbers together, and all the variables

14x-50=0

We move all terms containing x to the left, all other terms to the right

14x=50

x=50/14

x=3+4/7

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