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(21x-3)(5x+1)=180
We move all terms to the left:
(21x-3)(5x+1)-(180)=0
We multiply parentheses ..
(+105x^2+21x-15x-3)-180=0
We get rid of parentheses
105x^2+21x-15x-3-180=0
We add all the numbers together, and all the variables
105x^2+6x-183=0
a = 105; b = 6; c = -183;
Δ = b2-4ac
Δ = 62-4·105·(-183)
Δ = 76896
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{76896}=\sqrt{144*534}=\sqrt{144}*\sqrt{534}=12\sqrt{534}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-12\sqrt{534}}{2*105}=\frac{-6-12\sqrt{534}}{210} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+12\sqrt{534}}{2*105}=\frac{-6+12\sqrt{534}}{210} $
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