(21x-5)+(10x+11)=50

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Solution for (21x-5)+(10x+11)=50 equation: 



(21x-5)+(10x+11)=50

We move all terms to the left:

(21x-5)+(10x+11)-(50)=0

We get rid of parentheses

21x+10x-5+11-50=0

We add all the numbers together, and all the variables

31x-44=0

We move all terms containing x to the left, all other terms to the right

31x=44

x=44/31

x=1+13/31

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