(21x-8)=(23x+12)

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Solution for (21x-8)=(23x+12) equation: 



(21x-8)=(23x+12)

We move all terms to the left:

(21x-8)-((23x+12))=0

We get rid of parentheses

21x-((23x+12))-8=0



We calculate terms in parentheses: -((23x+12)), so:

(23x+12)

We get rid of parentheses

23x+12

Back to the equation:

-(23x+12)



We get rid of parentheses

21x-23x-12-8=0

We add all the numbers together, and all the variables

-2x-20=0

We move all terms containing x to the left, all other terms to the right

-2x=20

x=20/-2

x=-10

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