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(22+2x)(18+2x)=1440
We move all terms to the left:
(22+2x)(18+2x)-(1440)=0
We add all the numbers together, and all the variables
(2x+22)(2x+18)-1440=0
We multiply parentheses ..
(+4x^2+36x+44x+396)-1440=0
We get rid of parentheses
4x^2+36x+44x+396-1440=0
We add all the numbers together, and all the variables
4x^2+80x-1044=0
a = 4; b = 80; c = -1044;
Δ = b2-4ac
Δ = 802-4·4·(-1044)
Δ = 23104
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{23104}=152$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(80)-152}{2*4}=\frac{-232}{8} =-29 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(80)+152}{2*4}=\frac{72}{8} =9 $
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