(22-2x)(16-2x)=112

Solution for (22-2x)(16-2x)=112 equation:

(22-2x)(16-2x)=112

We move all terms to the left:

(22-2x)(16-2x)-(112)=0

We add all the numbers together, and all the variables

(-2x+22)(-2x+16)-112=0

We multiply parentheses ..

(+4x^2-32x-44x+352)-112=0

We get rid of parentheses

4x^2-32x-44x+352-112=0

We add all the numbers together, and all the variables

4x^2-76x+240=0

a = 4; b = -76; c = +240;
Δ = b2-4ac
Δ = -762-4·4·240
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1936}=44$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-76)-44}{2*4}=\frac{32}{8}
=4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-76)+44}{2*4}=\frac{120}{8}
=15
$