(22-2x)(28-2x)=520

Solution for (22-2x)(28-2x)=520 equation:

(22-2x)(28-2x)=520

We move all terms to the left:

(22-2x)(28-2x)-(520)=0

We add all the numbers together, and all the variables

(-2x+22)(-2x+28)-520=0

We multiply parentheses ..

(+4x^2-56x-44x+616)-520=0

We get rid of parentheses

4x^2-56x-44x+616-520=0

We add all the numbers together, and all the variables

4x^2-100x+96=0

a = 4; b = -100; c = +96;
Δ = b2-4ac
Δ = -1002-4·4·96
Δ = 8464
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{8464}=92$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-100)-92}{2*4}=\frac{8}{8}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-100)+92}{2*4}=\frac{192}{8}
=24
$