(227+229x)/(4+x)=143

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Solution for (227+229x)/(4+x)=143 equation: 


D( x )

x+4 = 0

x+4 = 0

x+4 = 0

x+4 = 0 // - 4

x = -4

x in (-oo:-4) U (-4:+oo)

(229*x+227)/(x+4) = 143 // - 143

(229*x+227)/(x+4)-143 = 0

(229*x+227)/(x+4)+(-143*(x+4))/(x+4) = 0

229*x-143*(x+4)+227 = 0

86*x-345 = 0

(86*x-345)/(x+4) = 0

(86*x-345)/(x+4) = 0 // * x+4

86*x-345 = 0

86*x-345 = 0 // + 345

86*x = 345 // : 86

x = 345/86

x = 345/86

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