(22x+1)+(9x-3)+(42x-3x)=180

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Solution for (22x+1)+(9x-3)+(42x-3x)=180 equation: 



(22x+1)+(9x-3)+(42x-3x)=180

We move all terms to the left:

(22x+1)+(9x-3)+(42x-3x)-(180)=0

We add all the numbers together, and all the variables

(22x+1)+(9x-3)+(+39x)-180=0

We get rid of parentheses

22x+9x+39x+1-3-180=0

We add all the numbers together, and all the variables

70x-182=0

We move all terms containing x to the left, all other terms to the right

70x=182

x=182/70

x=2+3/5

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