(22x-2)-(9x+21)=3x+27

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Solution for (22x-2)-(9x+21)=3x+27 equation: 



(22x-2)-(9x+21)=3x+27

We move all terms to the left:

(22x-2)-(9x+21)-(3x+27)=0

We get rid of parentheses

22x-9x-3x-2-21-27=0

We add all the numbers together, and all the variables

10x-50=0

We move all terms containing x to the left, all other terms to the right

10x=50

x=50/10

x=5

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