(23+(3x+5)-180)+(23+(3x+5))=180

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Solution for (23+(3x+5)-180)+(23+(3x+5))=180 equation: 



(23+(3x+5)-180)+(23+(3x+5))=180

We move all terms to the left:

(23+(3x+5)-180)+(23+(3x+5))-(180)=0



We calculate terms in parentheses: +(23+(3x+5)-180), so:

23+(3x+5)-180

determiningTheFunctionDomain
(3x+5)+23-180

We add all the numbers together, and all the variables

(3x+5)-157

We get rid of parentheses

3x+5-157

We add all the numbers together, and all the variables

3x-152

Back to the equation:

+(3x-152)





We calculate terms in parentheses: +(23+(3x+5)), so:

23+(3x+5)

determiningTheFunctionDomain
(3x+5)+23

We get rid of parentheses

3x+5+23

We add all the numbers together, and all the variables

3x+28

Back to the equation:

+(3x+28)



We get rid of parentheses

3x+3x-152+28-180=0

We add all the numbers together, and all the variables

6x-304=0

We move all terms containing x to the left, all other terms to the right

6x=304

x=304/6

x=50+2/3

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