(23-2x)+(9x-5)=39

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Solution for (23-2x)+(9x-5)=39 equation: 



(23-2x)+(9x-5)=39

We move all terms to the left:

(23-2x)+(9x-5)-(39)=0

We add all the numbers together, and all the variables

(-2x+23)+(9x-5)-39=0

We get rid of parentheses

-2x+9x+23-5-39=0

We add all the numbers together, and all the variables

7x-21=0

We move all terms containing x to the left, all other terms to the right

7x=21

x=21/7

x=3

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