(23-2x)+(9x-5)=39

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Solution for (23-2x)+(9x-5)=39 equation:



(23-2x)+(9x-5)=39
We move all terms to the left:
(23-2x)+(9x-5)-(39)=0
We add all the numbers together, and all the variables
(-2x+23)+(9x-5)-39=0
We get rid of parentheses
-2x+9x+23-5-39=0
We add all the numbers together, and all the variables
7x-21=0
We move all terms containing x to the left, all other terms to the right
7x=21
x=21/7
x=3

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