(23/20)x=92

Solution for (23/20)x=92 equation:

(23/20)x=92

We move all terms to the left:

(23/20)x-(92)=0


Domain of the equation: 20)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+23/20)x-92=0

We multiply parentheses

23x^2-92=0

a = 23; b = 0; c = -92;
Δ = b2-4ac
Δ = 02-4·23·(-92)
Δ = 8464
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{8464}=92$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-92}{2*23}=\frac{-92}{46}
=-2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+92}{2*23}=\frac{92}{46}
=2
$