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(23x-5)(21x+5)=360
We move all terms to the left:
(23x-5)(21x+5)-(360)=0
We multiply parentheses ..
(+483x^2+115x-105x-25)-360=0
We get rid of parentheses
483x^2+115x-105x-25-360=0
We add all the numbers together, and all the variables
483x^2+10x-385=0
a = 483; b = 10; c = -385;
Δ = b2-4ac
Δ = 102-4·483·(-385)
Δ = 743920
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{743920}=\sqrt{16*46495}=\sqrt{16}*\sqrt{46495}=4\sqrt{46495}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-4\sqrt{46495}}{2*483}=\frac{-10-4\sqrt{46495}}{966} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+4\sqrt{46495}}{2*483}=\frac{-10+4\sqrt{46495}}{966} $
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