(24+2x)(16+2x)=0

Solution for (24+2x)(16+2x)=0 equation:

(24+2x)(16+2x)=0

We add all the numbers together, and all the variables

(2x+24)(2x+16)=0

We multiply parentheses ..

(+4x^2+32x+48x+384)=0

We get rid of parentheses

4x^2+32x+48x+384=0

We add all the numbers together, and all the variables

4x^2+80x+384=0

a = 4; b = 80; c = +384;
Δ = b2-4ac
Δ = 802-4·4·384
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(80)-16}{2*4}=\frac{-96}{8}
=-12
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(80)+16}{2*4}=\frac{-64}{8}
=-8
$