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(24+2x)(18+2x)=1512
We move all terms to the left:
(24+2x)(18+2x)-(1512)=0
We add all the numbers together, and all the variables
(2x+24)(2x+18)-1512=0
We multiply parentheses ..
(+4x^2+36x+48x+432)-1512=0
We get rid of parentheses
4x^2+36x+48x+432-1512=0
We add all the numbers together, and all the variables
4x^2+84x-1080=0
a = 4; b = 84; c = -1080;
Δ = b2-4ac
Δ = 842-4·4·(-1080)
Δ = 24336
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{24336}=156$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(84)-156}{2*4}=\frac{-240}{8} =-30 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(84)+156}{2*4}=\frac{72}{8} =9 $
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