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(24+x)(15+x)=900
We move all terms to the left:
(24+x)(15+x)-(900)=0
We add all the numbers together, and all the variables
(x+24)(x+15)-900=0
We multiply parentheses ..
(+x^2+15x+24x+360)-900=0
We get rid of parentheses
x^2+15x+24x+360-900=0
We add all the numbers together, and all the variables
x^2+39x-540=0
a = 1; b = 39; c = -540;
Δ = b2-4ac
Δ = 392-4·1·(-540)
Δ = 3681
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3681}=\sqrt{9*409}=\sqrt{9}*\sqrt{409}=3\sqrt{409}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(39)-3\sqrt{409}}{2*1}=\frac{-39-3\sqrt{409}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(39)+3\sqrt{409}}{2*1}=\frac{-39+3\sqrt{409}}{2} $
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