(24-c+c)(24-c-c)=96

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Solution for (24-c+c)(24-c-c)=96 equation: 



(24-c+c)(24-c-c)=96

We move all terms to the left:

(24-c+c)(24-c-c)-(96)=0

We add all the numbers together, and all the variables

24(-2c+24)-96=0

We multiply parentheses

-48c+576-96=0

We add all the numbers together, and all the variables

-48c+480=0

We move all terms containing c to the left, all other terms to the right

-48c=-480

c=-480/-48

c=+10

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