(24/2x-6)+(1/x-3)=13

Solution for (24/2x-6)+(1/x-3)=13 equation:

D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(24/2)*x+1/x-6-3 = 13 // - 13

(24/2)*x+1/x-13-6-3 = 0

12*x^1+1*x^-1-22*x^0 = 0

(12*x^2-22*x^1+1*x^0)/(x^1) = 0 // * x^2

x^1*(12*x^2-22*x^1+1*x^0) = 0

x^1

12*x^2-22*x+1 = 0

12*x^2-22*x+1 = 0

DELTA = (-22)^2-(1*4*12)

DELTA = 436

DELTA > 0

x = (436^(1/2)+22)/(2*12) or x = (22-436^(1/2))/(2*12)

x = (2*109^(1/2)+22)/24 or x = (22-2*109^(1/2))/24

x in { (22-2*109^(1/2))/24, (2*109^(1/2)+22)/24} 

x in { (22-2*109^(1/2))/24, (2*109^(1/2)+22)/24 }