(24/3m)+4=40/m

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Solution for (24/3m)+4=40/m equation: 


D( m )

m = 0

m = 0

m = 0

m in (-oo:0) U (0:+oo)

(24/3)*m+4 = 40/m // - 40/m

(24/3)*m-(40/m)+4 = 0

(24/3)*m-40*m^-1+4 = 0

8*m^1-40*m^-1+4*m^0 = 0

(8*m^2+4*m^1-40*m^0)/(m^1) = 0 // * m^2

m^1*(8*m^2+4*m^1-40*m^0) = 0

m^1

8*m^2+4*m-40 = 0

8*m^2+4*m-40 = 0

DELTA = 4^2-(-40*4*8)

DELTA = 1296

DELTA > 0

m = (1296^(1/2)-4)/(2*8) or m = (-1296^(1/2)-4)/(2*8)

m = 2 or m = -5/2

m in { -5/2, 2} 

m in { -5/2, 2 }

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