(24/x-3)+(24/x+3)=6

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Solution for (24/x-3)+(24/x+3)=6 equation: 



(24/x-3)+(24/x+3)=6

We move all terms to the left:

(24/x-3)+(24/x+3)-(6)=0



Domain of the equation: x-3)!=0

x∈R





Domain of the equation: x+3)!=0

x∈R



We get rid of parentheses

24/x+24/x-3+3-6=0

We multiply all the terms by the denominator


-3*x+3*x-6*x+24+24=0

We add all the numbers together, and all the variables

-6x+48=0

We move all terms containing x to the left, all other terms to the right

-6x=-48

x=-48/-6

x=+8

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