(24/y)*y+2*(24/y)+3y=0

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Solution for (24/y)*y+2*(24/y)+3y=0 equation:


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

3*y+2*(24/y)+(24/y)*y = 0

3*y^1+48*y^-1+24*y^0 = 0

(3*y^2+24*y^1+48*y^0)/(y^1) = 0 // * y^2

y^1*(3*y^2+24*y^1+48*y^0) = 0

y^1

3*y^2+24*y+48 = 0

3*y^2+24*y+48 = 0

DELTA = 24^2-(3*4*48)

DELTA = 0

y = -24/(2*3)

y = -4 or y = -4

y in { -4, -4}

y in { -4, -4 }

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