(240/y+3)(y-4y)=240

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Solution for (240/y+3)(y-4y)=240 equation: 



(240/y+3)(y-4y)=240

We move all terms to the left:

(240/y+3)(y-4y)-(240)=0



Domain of the equation: y+3)(y-4y)!=0

y∈R



We add all the numbers together, and all the variables

(240/y+3)(-3y)-240=0

We multiply parentheses ..

(-720y^2-9y)-240=0

We get rid of parentheses

-720y^2-9y-240=0

a = -720; b = -9; c = -240;
Δ = b2-4ac
Δ = -92-4·(-720)·(-240)
Δ = -691119
Delta is less than zero, so there is no solution for the equation

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