(25+2x)(40+2x)=1000

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Solution for (25+2x)(40+2x)=1000 equation:



(25+2x)(40+2x)=1000
We move all terms to the left:
(25+2x)(40+2x)-(1000)=0
We add all the numbers together, and all the variables
(2x+25)(2x+40)-1000=0
We multiply parentheses ..
(+4x^2+80x+50x+1000)-1000=0
We get rid of parentheses
4x^2+80x+50x+1000-1000=0
We add all the numbers together, and all the variables
4x^2+130x=0
a = 4; b = 130; c = 0;
Δ = b2-4ac
Δ = 1302-4·4·0
Δ = 16900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16900}=130$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(130)-130}{2*4}=\frac{-260}{8} =-32+1/2 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(130)+130}{2*4}=\frac{0}{8} =0 $

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