(25-3x)(x+16)=0

Solution for (25-3x)(x+16)=0 equation:

(25-3x)(x+16)=0

We add all the numbers together, and all the variables

(-3x+25)(x+16)=0

We multiply parentheses ..

(-3x^2-48x+25x+400)=0

We get rid of parentheses

-3x^2-48x+25x+400=0

We add all the numbers together, and all the variables

-3x^2-23x+400=0

a = -3; b = -23; c = +400;
Δ = b2-4ac
Δ = -232-4·(-3)·400
Δ = 5329
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5329}=73$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-23)-73}{2*-3}=\frac{-50}{-6}
=8+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-23)+73}{2*-3}=\frac{96}{-6}
=-16
$