(25/n)=(2/7)/30

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Solution for (25/n)=(2/7)/30 equation: 


D( n )

n = 0

n = 0

n = 0

n in (-oo:0) U (0:+oo)

25/n = (2/7)/30 // - (2/7)/30

25/n-((2/7)/30) = 0

25/n-1/105 = 0

25*n^-1 = 1/105 // : 25

n^-1 = 1/2625

-1 < 0

1/(n^1) = 1/2625 // * n^1

1 = 1/2625*n^1 // : 1/2625

2625 = n^1

n = 2625

n = 2625

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